SOLUTION: I need some help finishing this problem. The instructions say to find the equation of a line that passes through (-4, 3)and that is parallel to 2x+3y=5. Here's what I have so far:

Algebra ->  Linear-equations -> SOLUTION: I need some help finishing this problem. The instructions say to find the equation of a line that passes through (-4, 3)and that is parallel to 2x+3y=5. Here's what I have so far:       Log On


   

Question 819966: I need some help finishing this problem. The instructions say to find the equation of a line that passes through (-4, 3)and that is parallel to 2x+3y=5. Here's what I have so far: 2x+3y=5
3y=5-2x
y=5/3-2/3x
y=-2/3x+5/3
m=2/3
y-3=-2/3(x-(-4))
I'm not sure what to do here. Do I simplify? How would I simplify it?
would i just distribute the two thirds? I don't know what to do after the distribution.
Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 

Hi,

equation of a line that passes through (-4, 3)and that is parallel to 2x+3y=5.

y-3=+%28-2%2F3%29%28x-%28-4%29%29  Good Work!  

y-3=+%28-2%2F3%29%28x%2B+4%29%29  |This would be Point-Slope form

y=+%28-2%2F3%29x++-+8%2F3+%2B+3  

y=+%28-2%2F3%29x++%2B+1%2F3   |This would be slope-intercept form

Standard Form:

  2x + 3y = 1