SOLUTION: A box contains nickels, dimes and quarters worth a total of $2.10. There are twice as many dimes as quarters, and the number of nickels is two less than the number of dimes. How ma
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Question 819944: A box contains nickels, dimes and quarters worth a total of $2.10. There are twice as many dimes as quarters, and the number of nickels is two less than the number of dimes. How many of each coin are there? Answer by TimothyLamb(4379) (Show Source):
You can put this solution on YOUR website! 5n + 10d + 25q = 210
d = 2q
n = d - 2
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5n + 10d + 25q = 210
0n + d - 2q = 0
n - d + 0q = -2
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solve the above system of linear equations for n, d, and q:
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answer:
n = 6
d = 8
q = 4
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