SOLUTION: The sides of an isosceles triangle are 29, 29, and 22m long. What is the area of the triangle?

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Question 819918: The sides of an isosceles triangle are 29, 29, and 22m long. What is the area of the triangle?
Found 2 solutions by josgarithmetic, richwmiller:
Answer by josgarithmetic(39617) About Me  (Show Source):
You can put this solution on YOUR website!
The altitude divides the isosceles triangle into two right triangles in which base is 11 m and hypotenuse is 29 m.

Find altitude: Altitude is a leg of each right triangle.
a%5E2%2B11%5E2=29%5E2
a=sqrt%2829%5E2-11%5E2%29

area of the two right triangles: 2%2A%281%2F2%2911%2Aa
11%2Aa
highlight_green%2811%2Asqrt%2829%5E2-11%5E2%29%29
Just compute that.

Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
the base is 22
1/2 base *height a=1/2b*h where b=22
the height is y in x^2+y^2=z^2
where x=11 and z=29
11^2+y^2=29^2
y^2+121 = 841
y^2 = 720
y=12sqrt(5)=26.8328
h=y
a=1/2b*h
a=1/2*22*26.8328=295.16097