Question 819917: In a survey of 2480 golfer, 15% said they were left handed. The survey's margin of error was 3%. construct a confidence interval for the proportion of left-handed golfers.
Please show me calculator keys to hit on the TI-83 calculator so I can use it in the future
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! In a survey of 2480 golfer, 15% said they were left handed. The survey's margin of error was 3%. construct a confidence interval for the proportion of left-handed golfers.
Please show me calculator keys to hit on the TI-83 calculator so I can use it in the future
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CI:: 0.15-0.03 < p < 0.15+0.03
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Comment: The TI-83 has its CI functions under button STAT
This CI would be generated under 1-PropZInt.
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BUT, you are told p-hat = 0.15 and ME = 0.03,
so you do not need a calculator to write
down the CI:: p-hat-ME < p < p-hat+ME
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Cheers,
Stan H.
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