SOLUTION: I need to fence a rectangular garden to keep critters out. The garden's length is 5 feet less than twice its width, and the total area is 150 sq. ft. Using a method other than fac
Algebra ->
Customizable Word Problem Solvers
-> Misc
-> SOLUTION: I need to fence a rectangular garden to keep critters out. The garden's length is 5 feet less than twice its width, and the total area is 150 sq. ft. Using a method other than fac
Log On
Question 819912: I need to fence a rectangular garden to keep critters out. The garden's length is 5 feet less than twice its width, and the total area is 150 sq. ft. Using a method other than factoring to solve, what length of fence do I need to surround the garden?
my work: i drew a chart
5 feet less than twice the width is.... 2x-5
must be solved algebraically Answer by ewatrrr(24785) (Show Source):
Hi,
Rectangle: width x and length(2x-5), area = 150ft^2, find Perimeter
A = x(2x-5) = 150f^2
2x^2 -5x - 150 = 0
(2x +15)(x -10) = 0 x = 10ft (tossing out negative solution for unit measure
Rectangle: width of 10ft, length of 15ft
P = 50ft of fencing will be needed
