SOLUTION: Two cars leave town at 11am. going in the same direction. One travels a 40mph and the other travels 45mph. What time will it be when the faster car is ahead by 25 miles? I would li

Algebra ->  Customizable Word Problem Solvers  -> Travel -> SOLUTION: Two cars leave town at 11am. going in the same direction. One travels a 40mph and the other travels 45mph. What time will it be when the faster car is ahead by 25 miles? I would li      Log On

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Question 819753: Two cars leave town at 11am. going in the same direction. One travels a 40mph and the other travels 45mph. What time will it be when the faster car is ahead by 25 miles? I would like to know the formula of how you come up with the answer please & Thank You
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
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speed of faster car relative to slower car = 5 mph
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s = d / t
t = d / s
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t = (25 miles) / (5 miles / hour)
t = 5 hours
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answer:
11 + 5 = 16:00 hours or 4:00 pm
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