SOLUTION: a number, one third of that number, and one fourth of that number are added. the result is 57. what is the original number ?

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Question 819699: a number, one third of that number, and one fourth of that number are added. the result is 57. what is the original number ?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
let number be x
x+x/3 +x/4 = =57
multiply the equation by 12
12x+4x+3x=12*57
19x=12*57
x=12*57/19
x=36