SOLUTION: Find two consecutive odd integers that three times the larger is 21 more than twice the smaller.

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Question 819686: Find two consecutive odd integers that three times the larger is 21 more than twice the smaller.
Answer by CubeyThePenguin(3113) About Me  (Show Source):
You can put this solution on YOUR website!
consecutive odd integers: x, (x+2)

3(x+2) = 21 + 2x
3x + 6 = 2x + 21
x = 15

The integers are 15 and 17.