Question 819421: The length of a rectangle is 3 feet longer than twice the width. If the area is 54 square feet, find the dimensions of the rectangle.
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! L = 2w + 3
Lw = 54
(2w + 3)w = 54
2ww + 3w - 54 = 0
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the above quadratic equation is in standard form, with a=2, b=3, and c=-54
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to solve the quadratic equation, by using the quadratic formula, plug this:
2 3 -54
into this: https://sooeet.com/math/quadratic-equation-solver.php
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the two real roots (i.e. the two x-intercepts), of the quadratic are:
w = 4.5
w = -6
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negative width doesn't make sense, so use the positive root
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w = 4.5 ft
L = 12 ft
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