SOLUTION: Here is the offending problem:
6e^5t = 18e^3t+2
I'm not sure how to start this one. My professor didn't give us an example like this that I can reference. Here is my attempt
Algebra ->
Exponential-and-logarithmic-functions
-> SOLUTION: Here is the offending problem:
6e^5t = 18e^3t+2
I'm not sure how to start this one. My professor didn't give us an example like this that I can reference. Here is my attempt
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Question 81933: Here is the offending problem:
6e^5t = 18e^3t+2
I'm not sure how to start this one. My professor didn't give us an example like this that I can reference. Here is my attempt:
6e^5t = 18e^3t+2
6e^5t - 18e^3t+2 =0
6(e^5t - 2e^3t+2) = 0
At this point I am lost. Answer by scott8148(6628) (Show Source):
You can put this solution on YOUR website! 6e^(5t)=18e^(3t+2) ... dividing by 6 gives e^(5t)=2e^(3t+2) ... taking natural log gives 5t=ln(2)+3t+2
subtracting 3t gives 2t=ln(2)+2 ... so t=1+((ln(2))/2)
