SOLUTION: Identify the CONIC(circle,ellipse,hyperbola) and state the center 25x^2-4y^2-50x-16y-59=0

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: Identify the CONIC(circle,ellipse,hyperbola) and state the center 25x^2-4y^2-50x-16y-59=0      Log On


   

Question 81931This question is from textbook
: Identify the CONIC(circle,ellipse,hyperbola) and state the center
25x^2-4y^2-50x-16y-59=0 This question is from textbook

Answer by scott8148(6628) About Me  (Show Source):
You can put this solution on YOUR website!
rearranging and separating terms gives 25x^2-50x=4y^2+16y+59

completing the squares and factoring gives 25(x-1)^2=4(y+2)^2+43+25 rearranging again gives 25(x-1)^2-4(y+2)^2=68

the general form of a hyperbola is %28%28%28x-h%29%5E2%29%2Fa%29-%28%28%28y-k%29%5E2%29%2Fb%29=1 where (h,k) is the center

the center of this hyperbola is (1,-2)