Question 819058: Find the exponential equation whose graph passes through the points (-3,3/8) and (3,24)
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! Find the exponential equation whose graph passes through the points (-3,3/8) and (3,24)
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Form y = a*b^x
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(3/8) = a*b^(-3)
24 = a*b^3
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Divide the lower by the upper equation and solve for "b":
24/(3/8) = b^6
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64 = b^6
b = 2
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Now solve for "a":
24 = a*b^3
24 = a*2^3
24 = a*8
a = 3
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Equation:
y = 3*2^x
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Cheers,
Stan H.
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