SOLUTION: x^2-6x-19=(x+h)^2+k The answer I have to find looks like this ( )^2+ _____ This is a box shape This is my first final in college and I couldn't go to study sessions

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: x^2-6x-19=(x+h)^2+k The answer I have to find looks like this ( )^2+ _____ This is a box shape This is my first final in college and I couldn't go to study sessions      Log On


   



Question 819023: x^2-6x-19=(x+h)^2+k
The answer I have to find looks like this ( )^2+ _____ This is a box shape
This is my first final in college and I couldn't go to study sessions due to snow and ice. I have all other study questions correct.
I would appreciate any help.

Answer by josgarithmetic(39625) About Me  (Show Source):
You can put this solution on YOUR website!
Do you want to Complete the Square to put the left-member trinomial into the form of the right-member shown?

On the left side, x%5E2-6x, factorable into x%28x-6%29 represents the area of a rectangle, with 'length' x and 'height' x-6. Chop this into a square of x by x and x by (x-6)-x, chop the x by (x-6-x) piece into two equal parts from top to bottom, and arrange one of the pieces along the bottom of the x by x square. Now, a small square piece is missing in order to COMPLETE the SQUARE for what was essentially the area for the rectangle of x by x-6.

The missing square piece to add, which is the same as the term to add, is %28-6%2F2%29%5E2=9 square units.

ADD and SUBTRACT 9 to the left-hand member of your "equation":
x%5E2-6x-19%2B9-9
x%5E2-6x%2B9-19-9, essentially from commutative property of addition
%28x%5E2-6x%2B9%29-19-9, the association will not hurt anything here and in fact helps
...
Do you know what to do from here?