Question 818997: A perimeter of a triangle is 49 cm. The first side is 2 cm less than twice the second side,and the third side is 3 cm longer than the second side. Find the lenght of each side.
Found 2 solutions by josgarithmetic, MathTherapy:
Answer by josgarithmetic(39630)   (Show Source):
You can put this solution on YOUR website! x, y, z the sides.
perimeter, 49=x+y+z.
x=y-2, z=y+3.
Substitute into perimeter equation.
(y-2)+y+(y+3)=49
Solve for y and compute the other sides x and z.
Answer by MathTherapy(10557)  (Show Source):
You can put this solution on YOUR website!
A perimeter of a triangle is 49 cm. The first side is 2 cm less than twice the second side,and the third side is 3 cm longer than the second side. Find the lenght of each side.
Let length of second side be S
Then length of first side is: 2S - 2, and length of third side is: S + 3
Thus, S + 2S - 2 + S + 3 = 49
Solve this to determine S, or the second side. Thereafter, make the necessary substitutions to find the other two sides.
Then do a check!!
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