Question 818785: It is given that the force btw 2 particles is inversely proportional to the square of the distance bttw them. If the force is F when the distance between them is r, and cF when the distance is 5r, write down the value for c?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! f(d) = K/d^2
where d is the distance between the two particles
and K is the constant of proportionality for the equation of force between two particles
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case 1:
F = K/r^2
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since F and r represent given constant numbers in the problem statement, now we have a numeric value for K, albeit based upon the general constant terms F and r:
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K = Fr^2
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case 2:
cF = K/((5r)^2)
cF = K/((25)r^2)
cF = Fr^2/((25)r^2)
c = r^2/((25)r^2)
c = 1/25
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answer:
c = 0.04
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