SOLUTION: The length of one side of a square is 20 cm and another square a diagonal of length 20 cm. What is the difference between the areas of above two squares?

Algebra ->  Surface-area -> SOLUTION: The length of one side of a square is 20 cm and another square a diagonal of length 20 cm. What is the difference between the areas of above two squares?      Log On


   



Question 818778: The length of one side of a square is 20 cm and another square a diagonal of length 20 cm. What is the difference between the areas of above two squares?
Answer by jhunjiro(67) About Me  (Show Source):
You can put this solution on YOUR website!
Given:
L1=20
D2=20
Solution:
Area of square = s^2
first square
-
L=20=s
Area = 20^2
Area of 1st square = 400
2nd square:
D=20
will create a triangle.
-
D%5E2+=+s%5E2+%2B+s%5E2
D%5E2+=+2s%5E2+
20%5E2=2s%5E2
400=2s%5E2
+400%2F2=2s%5E2%2F2
+200=s%5E2
+sqrt+%28200%29=+sqrt+%28s%5E2%29+
+10+%28sqrt+%282%29%29=s
Area = +%2810+%28sqrt+%282%29%29%5E2%29
Area of the 2nd square = 200
Final Solution:
Difference between the Areas = Area of 1st - Area of 2nd
Area = 400 - 200
Area= 200
Final Answer:
the difference between the areas of above two squares is 200.