Question 818773: A shopper paid $7.70 for 2 containers of milk and 3 containers of apple juice. It would have cost 60 cents more for 2 containers of apple juice and 3 containers of milk. How much would it cost to buy one container of each?
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! 2m + 3j = 770
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3m + 2j = 770 + 60
3m + 2j = 830
3m = 830 - 2j
m = (830/3) - (2/3)j
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2m + 3j = 770
2((830/3) - (2/3)j) + 3j = 770
(1660/3) - (4/3)j + 3j = 770
(1660/3) - (4/3)j + (9/3)j = 770
(5/3)j = 770 - (1660/3)
(5/3)j = (2310/3) - (1660/3)
(5/3)j = (650/3)
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j = (650/3)(3/5)
j = (650/5)
j = (650/5)
j = 130
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m = (830/3) - (2/3)j
m = (830/3) - (2/3)130
m = (830/3) - (260/3)
m = (570/3)
m = 190
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recall that above we used cents (i.e. 770 cents = $7.70), so now we must convert back to dollars.
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answer:
milk = $1.90
juice = $1.30
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