SOLUTION: Prove that, 7log16/15+5log25/24+3log81/80=log2.

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Question 818767: Prove that, 7log16/15+5log25/24+3log81/80=log2.
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
Note: In the future please put parentheses around function arguments.


What we will be doing is using properties of logarithms (log%28a%2C+%28p%29%29+%2B+log%28a%2C+%28q%29%29+=+log%28a%2C+%28p%2Aq%29%29, log%28a%2C+%28p%29%29+-+log%28a%2C+%28q%29%29+=+log%28a%2C+%28p%2Fq%29%29 and/or n%2Alog%28a%2C+%28p%29%29+=+log%28a%2C+%28p%5En%29%29) to condense the entire left side into a single logarithm (hopefully log(2)).

We'll start by using the third property to move the coefficients of each log into its argument as its exponent:

Next we can use the first property to combine the three logs:

To make simplifying the argument easier, I am going to rewrite each numerator and denominator in terms of prime factors:

Now we can use the %28a%2Fb%29%5En+=+a%5En%2Fb%5En rule to raise each of these fractions to a power:

Using the a%5En+%2A+a%5Em+=+a%5E%28n%2Bm%29 rule to multiply the numerators and denominators:

The 3's and 5's all cancel out. And we can use the a%5En%2Fa%5Em+=+a%5E%28n-m%29 rule to divide the 2's:
log%28%282%5E%2828-27%29%29%29=log%28%282%29%29%29
log%28%282%5E1%29%29=log%28%282%29%29%29
log%28%282%29%29=log%28%282%29%29%29 Check!