SOLUTION: If area and perimeter of a rectangles are 120 sq m and 46m then what r the dimensions of a rectangle ....ans is 15 and 8 bt dont know how to solve it
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Question 818526: If area and perimeter of a rectangles are 120 sq m and 46m then what r the dimensions of a rectangle ....ans is 15 and 8 bt dont know how to solve it Answer by jhunjiro(67) (Show Source):
You can put this solution on YOUR website! Your Answer:
Given:
Area=120 sq m
Perimeter=46 meter
Solution:
P=2L+2W
-
(46 = 2L+2W)/2
23 = L+W
L = 23-W
Area= L x W
120 = LxW
120 = (23-W)x (W)
120 = 23W-W^2
W^2 - 23W + 120 = 0
(W-15)(W-8) = 0
W-15=0
W = 15
L = 23-W
L = 23-15
L = 8
Final Answer: 15 and 8.
