SOLUTION: find the exact solution if the solution is irrational then also fineeeeee approxiate solutions to the nearest tenth find two positive real numbers that differ by 2 and have the pr

Algebra ->  Rational-functions -> SOLUTION: find the exact solution if the solution is irrational then also fineeeeee approxiate solutions to the nearest tenth find two positive real numbers that differ by 2 and have the pr      Log On


   



Question 81834: find the exact solution if the solution is irrational then also fineeeeee approxiate solutions to the nearest tenth
find two positive real numbers that differ by 2 and have the product of ten

Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find two positive real numbers that differ by 2 and have the product of ten
EQUATIONS:
x-y=2 and xy=10
x=y+2
(y+2)y=10
y^2+2y-10 = 0
y = [-2+-sqrt(4-4*-10]/2
y = [-2+-2sqrt11]/2
y = [-1+-sqrt1]
Positive answer:
y= -1+sqrt11 = 2.316625
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Substitue to solve for x:
x=y+2
x=4.316625
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Cheers,
Stan H.