SOLUTION: Find three consecutive odd numbers where the product of the smaller numbers is 22 less than the square of the last number.
(this is what i did)
{{{n+(n+2)=(n+4)^2-22}}}
{{{2n+
Algebra ->
Polynomials-and-rational-expressions
-> SOLUTION: Find three consecutive odd numbers where the product of the smaller numbers is 22 less than the square of the last number.
(this is what i did)
{{{n+(n+2)=(n+4)^2-22}}}
{{{2n+
Log On
Question 818325: Find three consecutive odd numbers where the product of the smaller numbers is 22 less than the square of the last number.
(this is what i did) now i don't know how to take the exponent out..
the lesson I had, had two exponents cancelling each other like this.
