Question 818298: How do you solve:
(-2i)(1+6i)-(5i)(-1+2i)
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! sum = (-2i)(1 + 6i) - (5i)(-1 + 2i)
a - b
a = (-2i)(1 + 6i)
b = (5i)(-1 + 2i)
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recall: ii = -1
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a = (-2i)(1 + 6i)
a = -2i + (-2i)(6i)
a = -2i + (-12ii)
a = (-2i + 12)
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b = (5i)(-1 + 2i)
b = (-5i) + (10ii)
b = (-5i - 10)
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sum = a - b
sum = (-2i + 12) - (-5i - 10)
sum = -2i + 12 + 5i + 10
sum = 3i + 22
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answer:
22 + 3i
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