SOLUTION: How would I graph y-1=1/4(x+5) and y=2x-3 ? I know how to graph the second equation I just can't get the first one. Thanks

Algebra ->  Graphs -> SOLUTION: How would I graph y-1=1/4(x+5) and y=2x-3 ? I know how to graph the second equation I just can't get the first one. Thanks      Log On


   



Question 817962: How would I graph y-1=1/4(x+5) and y=2x-3 ? I know how to graph the second equation I just can't get the first one. Thanks
Answer by KMST(5328) About Me  (Show Source):
You can put this solution on YOUR website!
You probably graph y=2x-3 ,in slope-intercept form,
by starting with the y-intercept, point (0,-3),
and using the slope, 2, to mark all the other points,
knowing that as x increases by 1, y would increase by 2.

y-1=%281%2F4%29%28x%2B5%29 is in what we call point-slope form,
meaning that it tells you that the line goes through point (-5,1),
and has a slope of 1/4.
Look at it this way:
y-1=%281%2F4%29%28x%2B5%29<-->%28y-1%29%2F%28x%2B5%29=1%2F4<-->%28y-1%29%2F%28x-%28-5%29%29=1%2F4=slope .

You can start from point (-5,1),and know that
for every 1 unit increase in x, there is a 1/4 increase in y,
or for every 4 unit increase in x, there is a 1 unit increase in y.