Question 817820: Two pullers, one with radius of 2 inches and the other with radius 8 inches, are connected by a belt. If the 2 inch pulley is caused to rotate at 3 revolutions per minute, determine the revolutions per minute of the 8 inch pulley.
Found 2 solutions by TimothyLamb, lwsshak3:
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! c = 2 pi r
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a = 2 pi 2
a = 12.566371
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b = 2 pi 8
b = 50.265482
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revb/reva = (a/b)
revb = reva(a/b)
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revb = 3(12.566371/50.265482)
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revb = 0.75 rpm
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Answer by lwsshak3(11628)  (Show Source):
You can put this solution on YOUR website! Two pullers, one with radius of 2 inches and the other with radius 8 inches, are connected by a belt. If the 2 inch pulley is caused to rotate at 3 revolutions per minute, determine the revolutions per minute of the 8 inch pulley.
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2-inch pully:
..
8-inch pulley:
revolutions per minute of the 8 inch pulley=1.5 rev/min
***
..
note: For a given linear speed, angular speed is inversely proportional to the radius.
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