SOLUTION: [ The sum of the digits of a two-digit number is 13. When the digits are reversed, the new number is 27 more than the original number. What is the original number. ]

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: [ The sum of the digits of a two-digit number is 13. When the digits are reversed, the new number is 27 more than the original number. What is the original number. ]      Log On


   



Question 817707: [ The sum of the digits of a two-digit number is 13. When the digits are reversed, the new number is 27 more than the original number. What is the original number. ]
Found 2 solutions by dkppathak, TimothyLamb:
Answer by dkppathak(439) About Me  (Show Source):
You can put this solution on YOUR website!
) The sum of the digits of a two-digit number is 13.When the digits are reversed, the new number is 27 more than the original number.What is the original number.
let unit digit of number is x
ten digit of number is 13-x
number two digit =10xten digit +unit digit
=10(13-x)+x
=130-10x+x
=130-9x
if digit are reserved ten digit will be x and unit digit will be 13-x
reverse number will be =10x+13-x
=9x+13
as per given condition
reverse number -27= original number
9x+13-27=130-9x
9x+9x=130+14
18x =144
x=144/18=8
unit digit=x=8
ten digit =13-x=13-8=5
number =58
Answer two digit number is 58

Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
10b + a = N
10a + b = N + 27
10a + b - 27 = N
---
a + b = 13
a = 13 - b
---
10b + a = 10a + b - 27
9b = 9a - 27
9b = 9(13 - b) - 27
9b = 117 - 9b - 27
18b = 90
---
b = 5
a = 8
---
N = 58
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