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| Question 817659:  Set up an equation and solve: the area of a rectangle is 40 square feet. the length is 2 feet less than twice the width. find the dimensions.
 Answer by TimothyLamb(4379)
      (Show Source): 
You can put this solution on YOUR website! Lw = 40 L = 2w - 2
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 Lw = 40
 (2w - 2)w = 40
 2w^2 - 2w - 40 = 0
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 the above quadratic equation is in standard form, with a=2, b=-2, and c=-40
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 to solve the quadratic equation, plug this:
 2 -2 -40
 into this: https://sooeet.com/math/quadratic-equation-solver.php
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 the roots of the quadratic are:
 w = 5
 w = -4
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 negative width doesn't make sense for this problem, so use the positive root:
 w = 5
 L = 8
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