SOLUTION: Word problem. 2/3 red beads, 1/4 yellow and rest blue. there are 42 more red beads than blue beads. How many altogether? Here is what I have done. 2/3=8/12 1/4=3/12 8

Algebra ->  Numeric Fractions Calculators, Lesson and Practice -> SOLUTION: Word problem. 2/3 red beads, 1/4 yellow and rest blue. there are 42 more red beads than blue beads. How many altogether? Here is what I have done. 2/3=8/12 1/4=3/12 8      Log On


   



Question 817549: Word problem. 2/3 red beads, 1/4 yellow and rest blue. there are 42 more red beads than blue beads. How many altogether? Here is what I have done.

2/3=8/12 1/4=3/12 8/12 + 3/12= 11/12 then I did, 42 divided by 12 = 3.6
Now what? I am so confused and hate this. Thank you for your help!

Isobelle

Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
r = number of red
b = number of blue
y = number of yellow
r = b + 42 or b = r - 42 and I suppose r - b = 42
Fraction that are blue
1 - ( 2/3 + 1/4 )
1 - ( 8/12 + 3/12 )
1 - ( 11/12 )
b = 1/12
Since y is 1/4 and y = 3/12, y = 3b
Since r is 2/3 and r = 8/12, r = 8b
Combine r = b + 42 with r = 8b
This means that b + 42 = 8b
Subtract b from each side
42 = 7b
6 = b
So we have b = 6 , y = 3b and r = 8b
Since b + y + r = total
By substituting
6 + 3(6) + 8(6) = total
6 + 18 + 48 = 72