SOLUTION: Please help me figure this out. log(base7)x - log(base7)(3x-5)=1

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Question 817316: Please help me figure this out. log(base7)x - log(base7)(3x-5)=1
Answer by LinnW(1048) About Me  (Show Source):
You can put this solution on YOUR website!
log(base7)(7) = 1, think 7^1 = 7
so log(base7)(x) - log(base7)(3x-5) = log(base7)(7)
Since in general log(u/v) = log(u) - log(v)
log(base7)( x / (3x-5) ) = log(base7)(7)
So x / (3x-5) = 7/1
x = 7(3x-5)
x = 21x -35
-20x = -35
x = 35/20
x = 7/4