SOLUTION: i have a rectangle w/a perimiter of 98 ft. i need to find the value of x. the height on both sides = x+3 the width on both sides= 2x+1 i got 17.7 like this 98=2(2x+1) +

Algebra ->  Triangles -> SOLUTION: i have a rectangle w/a perimiter of 98 ft. i need to find the value of x. the height on both sides = x+3 the width on both sides= 2x+1 i got 17.7 like this 98=2(2x+1) +       Log On


   

Question 8172: i have a rectangle w/a perimiter of 98 ft.
i need to find the value of x.
the height on both sides = x+3
the width on both sides= 2x+1
i got 17.7 like this 98=2(2x+1) + 2(x-3)
98=6x-5
103=6x
i'm just not sure if i did it correctly
Answer by bonster(299) About Me  (Show Source):
You can put this solution on YOUR website!
2(x+3)+2(2x+1)=98
2x%2B%282%29%283%29%2B%282%29%282x%29%2B%282%29%281%29=98
2x+6+4x+2=98
6x+8=98
(6x+8)-8=98-8
6x=90
6x%2F6=90%2F6
x=15

the value of x=15
the height=(15+3)=18
the width=(2*15+1)=31