SOLUTION: Find the value of "a" for which the graph of the first equation is perpendicular to the graph of the second equation. Ex: y = ax - 5 ; 2y = 3x

Algebra ->  Linear-equations -> SOLUTION: Find the value of "a" for which the graph of the first equation is perpendicular to the graph of the second equation. Ex: y = ax - 5 ; 2y = 3x      Log On


   



Question 816906: Find the value of "a" for which the graph of the first equation is perpendicular to the graph of the second equation.
Ex:
y = ax - 5 ; 2y = 3x

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Find the value of "a" for which the graph of the first equation is
perpendicular to the graph of the second equation.
Ex:
y = ax - 5 ; 2y = 3x
Using the standard slope-intercept form for an equation of a line y = mx + b
where m is the slope and b the y-intercept.
2y = 3x 0r y+=+highlight%283%2F2%29x m = 3%2F2
Perpendicular lines have slopes that are negative reciprocals of one another:
y = ax - 5 m = %28-2%2F3%29 Note: %283%2F2%29%28-2%2F3%29+=+-1
+y+=+highlight%28-2%2F3%29x+-+5
a = %28-2%2F3%29
graphs of y+=+highlight%283%2F2%29x(Green) and +y+=+highlight%28-2%2F3%29x+-+5(Blue)