Question 816836: How many liters each of 25% and 60% alcohol solutions must be mixed together to make 40 liters of a 53% alcohol solution? Found 2 solutions by richwmiller, TimothyLamb:Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! w = weak solution volume
s = strong solution volume
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alcohol in the mixed solution:
0.25w + 0.60s = 0.53*40
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total volume in the mixed solution:
w + s = 40
w = 40 - s
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0.25w + 0.60s = 0.53*40
0.25(40 - s) + 0.60s = 21.2
10 - 0.25s + 0.60s = 21.2
0.35s = 11.2
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Answer:
s = 32 liters
w = 8 liters
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