Hi, log 3 + log (x + 1) = log (2x + 4) | 1st step would be to get them on one side of the EQ log 3 + log (x + 1)- log (2x + 4) = 0 | write as one Logarithm Apply: and Apply: 3x+ 3 = 2x + 4 x = 1 CHECKING our answer*** log 3 + log (x + 1) = log (2x + 4) log 3 + log (2) = log (6)