SOLUTION: An object is thrown upward from the top of a 144-foot building with and initial velocity of 128 feet per second. the height h of the object t secnds is given by the quadratic equat
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Question 816725: An object is thrown upward from the top of a 144-foot building with and initial velocity of 128 feet per second. the height h of the object t secnds is given by the quadratic equation h=-16t^2+128t+144. when will the object hit the ground? Answer by ewatrrr(24785) (Show Source):
Hi,
An object is thrown upward from the top of a 144-foot building with and initial velocity of 128 feet per second.
h = -16t^2+128t+144. when will the object hit the ground? when h = 0
-16t^2+128t+144 = 0
t^2 -8t - 9 = 0
(t-9)(t+1) = 0, t = 9sec
