SOLUTION: if r and s are the roots of the equation 2x^2-3x+4=o, what is 4r^2+7rs+4s^2?

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Question 816668: if r and s are the roots of the equation 2x^2-3x+4=o, what is 4r^2+7rs+4s^2?
Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
2x^2-3x+4=o, what is 4r^2+7rs+4s^2
4r^2+7rs+4s^2
in the quadratic ax^2+bx+c=0 if p & q are the root of the equation
p+q=-b/a
pq=c/a
Similarly
in 2x^2-3x+4=o
r+s=3/2
rs=2
4r^2+7rs+4s^2
4r^2+8rs +4s^2 -8rs+7rs
(2r+2s)^2-rs
4(r+s)^2-rs
4(3/2)-2
6-2
=4