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Question 816537: Please help me solve this problem. Thanks in advance!
A baseball is hit so that its height in feet after t seconds is
s(t) = -16t^2 + 44t + 4.
(a) How high is the baseball after 1 second?
(b) Find the maximum height of the baseball.
Answer by TimothyLamb(4379)   (Show Source):
You can put this solution on YOUR website! s(t) = -16t^2 + 44t + 4
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the above quadratic equation is in standard form, with a=-16, b=44, and c=4
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to solve the quadratic equation, plug this:
-16 44 4
into this: https://sooeet.com/math/quadratic-equation-solver.php
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from the solver above, the quadratic vertex is a maximum at ( t= 1.375, s(t)= 34.25 )
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The maximum height of the baseball is 34.25 ft
the baseball achieves that maximum height after 1.375 seconds
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Height of the baseball after 1 second:
s(1) = -16 + 44 + 4
s(1) = 32 ft
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