SOLUTION: The average is 40. The third is 12 more than the second is five times the first. the fourth is 8 less than the first find the numbers.
Algebra
->
Problems-with-consecutive-odd-even-integers
-> SOLUTION: The average is 40. The third is 12 more than the second is five times the first. the fourth is 8 less than the first find the numbers.
Log On
Word Problems: Problems with consecutive odd even integers
Word
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Problems-with-consecutive-odd-even-integers
Question 816464
:
The average is 40. The third is 12 more than the second is five times the first. the fourth is 8 less than the first find the numbers.
Answer by
CubeyThePenguin(3113)
(
Show Source
):
You can
put this solution on YOUR website!
first = a
second = b
third = c
fourth = d
a + b + c + d = 160
c = b + 12
c = 5a
d = a - 8.
Write everything in terms of one variable: a.
5a = b + 12 ---> b = 5a - 12
c = 5a
d = a - 8
a + b + c + d = 160
a + (5a - 12) + 5a + (a - 8) = 160
12a - 20 = 160
12a = 180
a = 15
The numbers are a = 15, b = 63, c = 75, and d = 7.