SOLUTION: How do you solve for x when it is in the denominator on both sides of a rational equation? And what are the restrictions for X? This is the problem:
4/x = 5/x - 1/2
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-> SOLUTION: How do you solve for x when it is in the denominator on both sides of a rational equation? And what are the restrictions for X? This is the problem:
4/x = 5/x - 1/2
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Question 81644This question is from textbook Algebra I
: How do you solve for x when it is in the denominator on both sides of a rational equation? And what are the restrictions for X? This is the problem:
4/x = 5/x - 1/2 This question is from textbook Algebra I
You can put this solution on YOUR website! The restrictions in this case is that x cannot equal to zero because you cannot divide by zero. = = [find the LCD (2x); multiply each term by the LCD]
.
8=10-x [cancel wherever possible]
8=10-x [solve for the x-term]
8-8=10-8-x
0=2-x
-2=2-2-x
-2=-x
-2/-1=-x/-1
2=x
.
check by plugging (x=2) back into the original equation and solve: = =
2=
2=2 [checks out]
