SOLUTION: A die is thrown four times. Determine the probability of throwing the following. (a) zero 3's (Round your answer to four decimal places.) (b) one 3 (Round your answer to fo

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Question 816315: A die is thrown four times. Determine the probability of throwing the following.
(a) zero 3's (Round your answer to four decimal places.)

(b) one 3 (Round your answer to four decimal places.)

(c) two 3's (Round your answer to four decimal places.)

(d) three 3's (Round your answer to four decimal places.)

(e) four 3's (Round your answer to five decimal places.)

Answer by ewatrrr(24785) About Me  (Show Source):
You can put this solution on YOUR website!
 
Hi,
Re Reply: note highlighted
Note: The probability of x successes in n trials is:
P = nCx* p%5Ex%2Aq%5E%28n-x%29 where p and q are the probabilities of success and failure respectively.
In this case p = 1/6. q = 5/6 and n = 4 nCx = n%21%2F%28x%21%28n-x%29%21%29
A die is thrown four times. Determine the probability of throwing the following.
(a) zero 3's (Round your answer to four decimal places.) %285%2F6%29%5E4 = .4823
P(x=0) = 4C0 = (5/6)^4
(b) one 3 (Round your answer to four decimal places.) highlight%284%29%281%2F6%29%5E1%285%2F6%29%5E3= .3858
P(x = 1) = 4C1((1/6)^1(5/6)^3
(c) two 3's (Round your answer to four decimal places.) 6%281%2F6%29%5E2%285%2F6%29%5E2= .1157
P(x = 2) = 4C2((1/6)^2(5/6)^2
(d) three 3's (Round your answer to four decimal places.)4%281%2F6%29%5E3%285%2F6%29%5E1 = .0154
P(x = 3) = 4C3((1/6)^3(5/6)^1
(e) four 3's (Round your answer to five decimal places.)%281%2F6%29%5E4%285%2F6%29%5E0= .00077
P(x = 4) = 4C4((1/6)^4(5/6)^0
Note: The probability of x successes in n trials is:
P = nCx* p%5Ex%2Aq%5E%28n-x%29 where p and q are the probabilities of success and failure respectively. In this case p = 1/6. q = 5/6 and n = 4 nCx = n%21%2F%28x%21%28n-x%29%21%29