SOLUTION: Can you please help me solve this with the Quadratic Equation? x^2+39x+360=0 When I tried it, I came up with -39 +/- sqrt(1521-56160)

Algebra ->  Quadratic Equations and Parabolas -> SOLUTION: Can you please help me solve this with the Quadratic Equation? x^2+39x+360=0 When I tried it, I came up with -39 +/- sqrt(1521-56160)       Log On


   



Question 816274: Can you please help me solve this with the Quadratic Equation?
x^2+39x+360=0
When I tried it, I came up with -39 +/- sqrt(1521-56160)

Found 2 solutions by TimothyLamb, Edwin McCravy:
Answer by TimothyLamb(4379) About Me  (Show Source):
You can put this solution on YOUR website!
x^2 + 39x + 360 = 0
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the above quadratic equation is in standard form, with a=1, b=39, and c=360
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to solve the quadratic equation, plug this:
1 39 360
into this: https://sooeet.com/math/quadratic-equation-solver.php
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the roots of the quadratic are:
x = -15
x = -24
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NOTE TO STUDENT:
please review the quadratic equation in standard form, AND the quadratic formula used to solve it.
the above online solver contains all that information in its pop-up help windows.
---
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Answer by Edwin McCravy(20056) About Me  (Show Source):
You can put this solution on YOUR website!
x²+39x+360 = 0

It can be factored:

(x+24)(x+15) = 0

x+24=0;  x+15=0
  x=-24;    x=-15

But you could have solved it using the quadratic formula.

You got the quadratic formula wrong and used b²-4bc instead of b²-4ac.

x+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29+ 

x+=+%28-39+%2B-+sqrt%28+39%5E2-4%2A1%2A360+%29%29%2F%282%2A1%29+

x+=+%28-39+%2B-+sqrt%281521-1440+%29%29%2F2+

x+=+%28-39+%2B-+9%29%2F2+

Using the +


x+=+%28-39+%2B+9%29%2F2+


x+=+%28-30%29%2F2+

x = -15   


Using the -


x+=+%28-39+-+9%29%2F2+


x+=+%28-48%29%2F2+

x = -24   

Edwin