SOLUTION: solve 12sin^2(x)+2sin(x)-2=0 for all solutions where x is in radians between 0 and 2pi

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Question 816104: solve 12sin^2(x)+2sin(x)-2=0 for all solutions where x is in radians between 0 and 2pi
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
solve 12sin^2(x)+2sin(x)-2=0 for all solutions where x is in radians between 0 and 2pi
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12sin%5E2%28x%29%2B2sin%28x%29-2=0
divide by 2
6sin%5E2%28x%29%2Bsin%28x%29-1=0
solve for sin(x)
(3sin(x)-1)(2sin(x)+1)=0
..
3sin(x)-1=0
sin(x)=1/3
x≈0.34, 2.80
or
2sin(x)+1=0
sin(x)=-1/2
x=7π/6,11π/6