SOLUTION: Simplify cscx- cosxcotx I rewrote the problem using reciprocals and quotients to get {{{1/sinx- 1/secx*cosx/sinx}}}. Then I multiplied the reciprocals of cosx and cotx to get {{{1

Algebra ->  Trigonometry-basics -> SOLUTION: Simplify cscx- cosxcotx I rewrote the problem using reciprocals and quotients to get {{{1/sinx- 1/secx*cosx/sinx}}}. Then I multiplied the reciprocals of cosx and cotx to get {{{1      Log On


   

Question 816076: Simplify cscx- cosxcotx
I rewrote the problem using reciprocals and quotients to get 1%2Fsinx-+1%2Fsecx%2Acosx%2Fsinx. Then I multiplied the reciprocals of cosx and cotx to get 1%2Fsinx-+1cosx%2Fsecxsinx I'm not sure what to do after that.
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
Simplify cscx- cosxcotx
I rewrote the problem using reciprocals and quotients to get 1%2Fsinx-+1%2Fsecx%2Acosx%2Fsinx. Then I multiplied the reciprocals of cosx and cotx to get 1%2Fsinx-+1cosx%2Fsecxsinx I'm not sure what to do after that.
===============
cscx- cosxcotx
---
= 1/sin - cos^2/sin
= (1 - cos^2)/sin
= sin^2/sin
= sin(x)