Question 81606: can someone please check this for me?
10/y-8 - 1/x+1
10/y-8-(1/y+1)
10/y-8-1/y-1
10/y+-9-1/y
10/y-1/y+-9
10/y-1/y-9
10-1/y-9
9/y-9 Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! 10/(y-8) - 1/(x+1)
=[10(x+1)-(y-8)]/[(y-8)(x+1)]
=[10y+10-y+8]/[(y-8)(x+1)]
=[9y+18]/[(y-8)(x+1)]
=[9(y+2)]/[(y-8)(x+1)]
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Cheers,
Stan H.