SOLUTION: i'm needing some help on how to expand this logarithm and i'm not real sure where to began: loga[(x^2y^-3)^4/(xy)]

Algebra ->  Exponential-and-logarithmic-functions -> SOLUTION: i'm needing some help on how to expand this logarithm and i'm not real sure where to began: loga[(x^2y^-3)^4/(xy)]      Log On


   

Question 81605: i'm needing some help on how to expand this logarithm and i'm not real sure where to began:

loga[(x^2y^-3)^4/(xy)]
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
loga[(x^2y^-3)^4/(xy)]
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Comment: All of this is log (base a) but I'm not repeating it.
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log[(x^8y^-12/(xy)]
= 8logx -12logy -log(xy)
=8logx -logy -logx - logy
= 7logx -2logy
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Cheers,
Stan H.