SOLUTION: a man has $.90 in nickels, dimes and quarters. Half of the coins are nickels, and a fourth of the are dimes. How many of each coin does he have?

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Question 816006: a man has $.90 in nickels, dimes and quarters. Half of the coins are nickels, and a fourth of the are dimes. How many of each coin does he have?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
10d+25q+5n=90,
n+d+q=x,
x/2=n,
x/4=d
d = 2, n = 4, q = 2, x = 8