SOLUTION: find the value of x: log6 (5x+9)=4 a. 3 b. 817.4 c. 261 d. 257.4 I have no clue where to even start with this problem. ive tried pluging the answers in the calculator

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: find the value of x: log6 (5x+9)=4 a. 3 b. 817.4 c. 261 d. 257.4 I have no clue where to even start with this problem. ive tried pluging the answers in the calculator      Log On


   



Question 815940: find the value of x: log6 (5x+9)=4
a. 3
b. 817.4
c. 261
d. 257.4


I have no clue where to even start with this problem. ive tried pluging the answers in the calculator but havnt had luck with that

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
+log%286%2C+%285x%2B9%29%29=4+
Solving equations where the variable is in a logarithm usually starts with using algebra and/or properties of logarithms to transform the equation into one of the following forms:
log(expression) = number
or
log(expression) = log(other_expression)

Your equation is already in the first form. So we can skip to the next stage: Eliminate the logarithms. With the first form we rewrite the equation in exponential form. In general log%28a%2C+%28p%29%29+=+n is equivalent to p+=+a%5En. Using this pattern on your equation we get:
5x%2B9=6%5E4+
which simplifies to:
5x%2B9=1296+
Now we solve. Subtracting 9:
5x=1287+
Divide by 5:
x=1287%2F5+
There are no fractions or mixed numbers in the given answers. So we convert the fraction to a decimal (by dividing 1287 by 5):
x=+257.4

P.S. The reason your calculator didn't help was that it does not understand base 6 logarithms. Calculators usually "know" base 10 ("log") and base e ("ln") logarithms. To use your calculator on this you would have to use the base conversion formula, log%28a%2C+%28p%29%29+=+log%28b%2C+%28p%29%29%2Flog%28b%2C+%28a%29%29, to convert the base 6 log to a base 10 or base e log:
+log%286%2C+%285x%2B9%29%29=4+
+log%28%285x%2B9%29%29%2Flog%28%286%29%29=4+
Now you could use trial and error of the possible answers to find out which one works.