Hi, sum of the squares of three consecutive integers(x+3)(x-1) = 0 x,(x+1),(x+2) is 14 3x^2 + 6x + 5 = 14 3x^2 + 6x -9 = x^2 + 2x - 3 = 0 (x+3)(x-1) = 0 (x+3)= 0 , x = -3 0r (x-1) = 0 , x = 1 three consecutive integers: -3, -2, -1 0r 1, 2, 3