SOLUTION: 5 log 3 + log 4 in single logarithm

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Question 815816: 5 log 3 + log 4 in single logarithm

Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
5log%28%283%29%29%2Blog%28%284%29%29
  • To go from two logs to one we need to either eliminate one of them or find a way to combine them. There's no way to eliminate a log from this expression so we will have to combine them.
  • There are two ways to combine logs:
    • Algebraically add them. This requires that the bases and arguments of the logs are the same. The bases of our logs are the same, 10, but the arguments are different, 3 and 4. Since there is no way to make the arguments be the same we will not be able to add the logs algebraically.
    • Use the log%28a%2C+%28p%29%29+%2B+log%28a%2C+%28q%29%29+=+log%28a%2C+%28p%2Aq%29%29 property of logs. This property requires that the logs have the same bases (which ours do) and have coefficients of 1 (which ours do not since the first log has a coefficient of 5). Fortunately there is a way to change the coefficient to a 1.
  • A property of logs, n%2Alog%28a%2C+%28p%29%29+=+log%28a%2C+%28p%5En%29%29, allows one to "move" a coefficient into the argument as its exponent. This is how we will handle the 5.
So our plan is to move the 5 using one property and then combine the logs using the other:
log%28%283%5E5%29%29%2Blog%28%284%29%29
which simplifies to:
log%28%28243%29%29%2Blog%28%284%29%29
Now we can use the other property to combine them:
log%28%28243%2A4%29%29
which simplifies to:
log(972)