Question 815649: Mon is 8 years younger than Ram. In two years, the age of Ram will be 2 less than twice Mon’s age. Find their present ages.
Answer by algebrahouse.com(1659)   (Show Source):
You can put this solution on YOUR website! x = Ram's present age
x - 8 = Mon's present age
x + 2 = Ram's age in 2 years {added 2 onto present age}
x - 6 = Mon's age in 2 years {added 2 onto present age}
x + 2 = 2(x - 6) - 2 {in two years, Ram will be 2 less than twice Mon}
x + 2 = 2x - 12 - 2 {used distributive property}
x + 2 = 2x - 14 {combined like terms}
2 = x - 14 {subtracted x from each side}
x = 16 {added 14 to each side}
x - 8 = 8 {substituted 16, in for x, into x - 8}
Ram is 16 and Mon is 8
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