Question 815645: Solve the system
y = x^2 - 4x - 15
y = 2x - 1
Answer by ankor@dixie-net.com(22740)   (Show Source):
You can put this solution on YOUR website! Solve the system
y = x^2 - 4x - 15
y = 2x - 1
y = y therefore
2x - 1 = x^2 - 4x - 15
0 = x^2 - 4x - 2x - 15 + 1
A quadratic equation, solve for x:
x^2 - 6x - 14 = 0
We have to use the quadratic formula to find x
Two solutions,
x = -1.796
x = 7.796
:
I'll let you find y for both solutions
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