SOLUTION: solve sin^2(t)=-5cos(t) for all solutions where t is in radians between 0 and 2pi. Give your answers accurate to 2 decimal places, as a list separated by commas

Algebra ->  Trigonometry-basics -> SOLUTION: solve sin^2(t)=-5cos(t) for all solutions where t is in radians between 0 and 2pi. Give your answers accurate to 2 decimal places, as a list separated by commas      Log On


   



Question 815619: solve sin^2(t)=-5cos(t) for all solutions where t is in radians between 0 and 2pi. Give your answers accurate to 2 decimal places, as a list separated by commas
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
solve sin^2(t)=-5cos(t) for all solutions where t is in radians between 0 and 2pi.
------------
Hint: sin^2 = 1 - cos^2